(2x^1+7)(2x^2-7x^1+3)=0

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Solution for (2x^1+7)(2x^2-7x^1+3)=0 equation: 


Simplifying
(2x + 7)(2x2 + -7x + 3) = 0

Reorder the terms:
(7 + 2x)(2x2 + -7x + 3) = 0

Reorder the terms:
(7 + 2x)(3 + -7x + 2x2) = 0

Multiply (7 + 2x) * (3 + -7x + 2x2)
(7(3 + -7x + 2x2) + 2x * (3 + -7x + 2x2)) = 0
((3 * 7 + -7x * 7 + 2x2 * 7) + 2x * (3 + -7x + 2x2)) = 0
((21 + -49x + 14x2) + 2x * (3 + -7x + 2x2)) = 0
(21 + -49x + 14x2 + (3 * 2x + -7x * 2x + 2x2 * 2x)) = 0
(21 + -49x + 14x2 + (6x + -14x2 + 4x3)) = 0

Reorder the terms:
(21 + -49x + 6x + 14x2 + -14x2 + 4x3) = 0

Combine like terms: -49x + 6x = -43x
(21 + -43x + 14x2 + -14x2 + 4x3) = 0

Combine like terms: 14x2 + -14x2 = 0
(21 + -43x + 0 + 4x3) = 0
(21 + -43x + 4x3) = 0

Solving
21 + -43x + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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